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3x^2+15x+25=-3x-2
We move all terms to the left:
3x^2+15x+25-(-3x-2)=0
We get rid of parentheses
3x^2+15x+3x+2+25=0
We add all the numbers together, and all the variables
3x^2+18x+27=0
a = 3; b = 18; c = +27;
Δ = b2-4ac
Δ = 182-4·3·27
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-18}{6}=-3$
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